Question

As a quality control check, a sample of acetone is taken from a process to determine the concentration of suspended particulate matter. An 850-mL sample was placed in a beaker and evaporated. The remaining suspended solids were determined to have a mass of 0.001 g. The specific gravity of acetone is 0.79 g/cm3. (a) Determine the concentration of the sample as mg/L. (b) Determine the concentration of the sample as ppm.

Answer 1

Answer on Question #53994 – Chemistry – General chemistry

Question:

As a quality control check, a sample of acetone is taken from a process to determine the concentration of suspended particulate matter. An 850-mL sample was placed in a beaker and evaporated. The remaining suspended solids were determined to have a mass of 0.001 g. The specific gravity of acetone is 0.79 g/cm³. (a) Determine the concentration of the sample as mg/L. (b) Determine the concentration of the sample as ppm.

Answer:

(a) The concentration of the samples is:

C = m/V, where m – the mass of solids and V – the studied volume.

Thus, C = 1 mg/0.85 L = 1.1765 mg/L

(b) The concentration in ppm:

C = m/M, where M is the mass of acetone (M = 850 mL × 0.79 g/mL = 671.5 g)

C = 1000 μg/671.5 g = 1.4892 ppm

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