Question #53845

If you have a 0.50 liter piston filled with air at 14.7 psi, what is the pressure on the piston when the volume increases to 0.65 liters assuming no temperature change?
1

Expert's answer

2015-08-03T07:07:52-0400

Answer on Question #53845 – Chemistry – General chemistry

Question:

If you have a 0.50 liter piston filled with air at 14.7 psi, what is the pressure on the piston when the volume increases to 0.65 liters assuming no temperature change?

Solution: Isothermal change of system is calculated according to the equation:


p1V1=p2V2p_1V_1 = p_2V_2

, where p1V1p_1V_1 – the initial volume and pressure and p2V2p_2V_2 – the final volume and pressure.

Thus, p2=p1V1/V2=(0.5l×14.7psi)/0.65l=11.31psi=77.979kPap_2 = p_1V_1/V_2 = (0.5 \, l \times 14.7 \, \text{psi}) / 0.65 \, l = 11.31 \, \text{psi} = 77.979 \, \text{kPa}

Answer: the final pressure is 11.31 psi.

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