Question #53845

If you have a 0.50 liter piston filled with air at 14.7 psi, what is the pressure on the piston when the volume increases to 0.65 liters assuming no temperature change?

Expert's answer

Answer on Question #53845 – Chemistry – General chemistry

Question:

If you have a 0.50 liter piston filled with air at 14.7 psi, what is the pressure on the piston when the volume increases to 0.65 liters assuming no temperature change?

Solution: Isothermal change of system is calculated according to the equation:


p1V1=p2V2p_1V_1 = p_2V_2

, where p1V1p_1V_1 – the initial volume and pressure and p2V2p_2V_2 – the final volume and pressure.

Thus, p2=p1V1/V2=(0.5l×14.7psi)/0.65l=11.31psi=77.979kPap_2 = p_1V_1/V_2 = (0.5 \, l \times 14.7 \, \text{psi}) / 0.65 \, l = 11.31 \, \text{psi} = 77.979 \, \text{kPa}

Answer: the final pressure is 11.31 psi.

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