Question

You need to dissolve CaCl2 in water to make a mixture that is 32.0% calcium chloride by mass. If the total mass of the mixture is 216.5 g, what masses of CaCl2 and water should be used?

Answer 1

Answer on Question #53622 – Chemistry – General chemistry

Question:

You need to dissolve CaCl₂ in water to make a mixture that is 32.0% calcium chloride by mass. If the total mass of the mixture is 216.5 g, what masses of CaCl₂ and water should be used?

Solution:

First of all, the mass of CaCl₂ should be found:

Since w(%) = [m(CaCl₂)/m(total)] × 100%, then m(CaCl₂) = (m(total) × w(%) / 100%.

Thus, m(CaCl₂) = (216.5 g × 32%) / 100% = 69.28 g

Taking into account that the total mass equals: m(total) = m(CaCl₂) + m(H₂O)

m(H₂O) = m(total) - m(CaCl₂) = 216.5 g – 69.28 g = 147.22 g

Answer: m(H₂O) = 147.22 g and m(CaCl₂) = 69.28 g

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