Which statement concerning relative rates of reaction is correct for the chemical equation given below?
2 CH3OH(g) + 3 O2(g) → 2 CO2(g) + 4 H2O(g)
The rate of appearance of H2O is two times the rate of appearance of CO2.
The rate of disappearance of CH3OH is equal to the rate of disapperance of O2.
The rate of disappearance of CH3OH is two times the rate of appearance of H2O.
The rate of appearance of H2O is four times the rate of disappearance of CH3OH.
The rate of disappearance of CH3OH is half the rate of appearance of CO2.
1
Expert's answer
2015-07-13T12:14:18-0400
Considering coefficients in the equation (2 before CO2 and 4 before H2O), the right answer is: The rate of appearance of H2O is two times the rate of appearance of CO2: 4(H2O)/2(CO2)=2
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