Question

How many mL of 0.25M solution of H2SO4 will react with 10mL of 0.25M solution of NaOH?

Answer 1

C_M — concentration of molarity (mol/L)

V — volume (L)

n — amount of substance (mol)

C_M (NaOH) = 0.25 M

V (NaOH) = 10 ml = 0.01 liters

$n(NaOH)=~C_M*~V =~ 0.25 * ~0.01 = ~0.0025 ~mol$

2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O

2 mol NaOH — 1mol H₂SO₄

0.0025 mol NaOH — X

X = 0.0025*1/2= 0.00125 mol H₂SO₄

$V(H_2SO_4)=~\cfrac {n}{C_M}= ~\cfrac {0.00125}{0.25}=~ 0.005 L=~5~ml$

Answer: 5 ml