Answer to Question #350840 in General Chemistry for breez

Question #350840

calculate the mass of titanium (0.125 cal.g * C) that requires 75.5 cal to heat the metal from 20.5 to 32.0



1
Expert's answer
2022-06-16T06:25:04-0400

C — specific heat capacity = 0.125

Q — heat energy = 75.5

∆T — change in temperature = 32-20.5=11.5

m — mass of substance = ?


Q=mCTQ=mC∆T


m=QCT=75.50.12511.5=52.52 gm = \cfrac {Q}{C∆T}=\cfrac {75.5}{0.125*11.5}= 52.52~g





Answer: 52.52 g









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