Question

The volume of a sample of a gas is 8.39 L at 33oC. What would be the volume if the temperature is changed to 265 K, while the pressure is constant?

Answer 1

T₀ — initial temperature = 33°C = 306 K

T — final temperature = 265 K

V₀ — initial volume = 8,39 liters

V — final volume = ?

Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant:

$\cfrac {V}{V_0}=\cfrac{T}{T_0}$

$V=~\cfrac {T*V_0}{T_0} = ~\cfrac {265*8,39}{306}=~ 7,27 ~l$

Answer: 7,27 liters