The volume of a sample of a gas is 8.39 L at 33oC. What would be the volume if the temperature is changed to 265 K, while the pressure is constant?
T0 — initial temperature = 33°C = 306 K
T — final temperature = 265 K
V0 — initial volume = 8,39 liters
V — final volume = ?
Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant:
"\\cfrac {V}{V_0}=\\cfrac{T}{T_0}"
"V=~\\cfrac {T*V_0}{T_0} = ~\\cfrac {265*8,39}{306}=~ 7,27 ~l"
Answer: 7,27 liters
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