Answer to Question #349668 in General Chemistry for car

Question

How much heat energy is required to change the temperature of 56.75 g of

water from 23.0 C to 56.7 C? (specific heat capacity of water is 4.18 kJ/(kg

OC))

Answer 1

We wish to determine the value of Q - the quantity of heat. To do so, we would use the equation Q = m•C•ΔT. The m and the C are known; the ΔT can be determined from the initial and final temperature. With three of the four quantities of the relevant equation known, we can substitute and solve for Q.

m = 56,75 g

C = 4,18

∆T = T₂ - T₁

$Q= 56,75×4.18×(56,7−23)=7994J = 7,99 kJ$

Answer: 7,99 kJ