Question

I have 130 liters of gas in a piston at a temperature of 250 o C. If

I cool the gas until the volume decreases to 85 liters, what will

temperature of the gas be?

Answer 1

T₀ — initial temperature = 250°C = 523 K

T — final temperature = ?

V₀ — initial volume = 130 liters

V — final volume = 85 liters

Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant:

$\cfrac {V}{V_0}=\cfrac{T}{T_0}$

$T=~\cfrac {V*T_0}{V_0} = ~\cfrac {85*523}{130}=~342~K =~ 69°C$

Answer: 69° C