Balance the each of the following half-reactions and write the net-equation
Al3+ (aq) + 3e- → Al (s) and Sn2+ (aq) + 2e- → Sn(s)
net-equation:
AlCl3 + Sn = SnCl2 + Al
Half-reaction:
Al3+ + 3 e- => Al
Sn – 2 e- => Sn2+
Balaned reaction:
2AlCl3 + 3Sn = 3SnCl2 + 2Al
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