Answer to Question #349066 in General Chemistry for baylee

Question

 In older airbags, sodium azide, NaN₃, was used as a source of nitrogen gas to rapidly inflate the airbag. This practice was mostly discontinued due to the high toxicity of sodium azide. The reaction of interest is 2 NaN_3 (s) → 2 Na _(s) + 3 N_2 (g) 

How many grams of N₂ are produced if a 35.0 g charge of NaN₃ decomposes?

Answer 1

first convert 75.0 g to Moles by dividing by 28g/mol. = 2.68 moles N₂

Based on the balanced equation reactants to product ratio are 2:3 for Azide: Nitrogen gas. This means for every 3 moles of Nitrogen gas produces, 2 moles of Sodium Azide are needed.

This is a dimensional analysis question by using the fence method.

Start with moles calculated from above.

2.68 Moles N₂ *(2 moles NaN₃/3 moles N₂)=1.79mol NaN₃(65g/mol)= 116.35 g or with sig. figs 116g NaN₃