Determine the molecular formula of alaxin C5H8nO5 if it's relative molecular Mass is 284
(Empirical formula) n = Molecular formula
(C5H8)nO5 = 284 ......... (I)
[(12*5) + (1*8)]n + (16*5) = 284
(60 + 8)n + 80 = 284
68n + 80 = 284
68n = 284 - 80 = 204
n = 204/68 = 3
Substitute for n = 3 in equation (I)
(C5H8)3O5
C15H24O5
Comments
Leave a comment