How many moles present in 23.3 Kg Ar ?
Solution:
The molar mass of argon (Ar) is 40 g/mol
Therefore,
Moles of Ar = (23.3 kg Ar) × (1000 g / 1 kg) × (1 mol Ar / 40 g Ar) = 582.5 mol Ar
Answer: 582.5 moles of argon (Ar)
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