Calculate the pressure in a 212 Liter tank containing 23.3 kg of argon gas at 25°C? ( atomic weight Ar - 40 )
V = 212 l
T = 25°C =298 K
M(Ar) = 40 g/mol
R = 8,31
n(Ar) = m / M = 23300 / 40= 582,5 mol
P = nRT / V = 582,5 *8,31*298/212= 6804,2
Answer: 6804,2 kPa
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