Answer to Question #347907 in General Chemistry for bruce

Question

Convert 80mL (4.03g) of acetic acid into moles of acetic acid

Answer 1

n(CH₃COOH) = m(CH₃COOH) / Mr(CH₃COOH)

n(CH₃COOH) = 4.03 g / 60,05 g/mol = 0.067 moles

C_m = 0.067 moles * 0.08 L = 5.36 * 10^-3 M