Answer to Question #347650 in General Chemistry for erlll

Question

if 500,000 kj of heat are released by the reaction, how grams of C12H26 must have been consumed

Answer 1

M_r(C₁₂H₂₆) = 170 g/mol

2C₁₂H₂₆ +37O₂ = 24CO₂ + 26H₂O +15026 kJ

340 g C₁₂H₂₆ — 15026 kJ

X — 500000 kJ

X = 340 * 500000 / 15026 = 11313,7 g

ANSWER: 11313.7 g C₁₂H₂₆