For the following overall cell reaction, write the oxidation and reduction half-reactions, calculate the standard cell potential, E^0cell and determine if the reaction is spontaneous or not. Show your work.
Fe^3+(aq) + Cu^+(aq) —> Fe^2+(aq) + Cu^2+(aq)
1.
Fe3+ + e- => Fe2+ — reduction half-reaction
Cu+ - e- => Cu2+ — oxidation half-reaction
2.
Fe3+ + 1e- => Fe2+ E0 = 0,771 V
Cu+ - 1e- => Cu2+ E0 = -0,16 V
E0cell = 0,771 + (-0,16) = 0,611 V
If E°cell > 0, then the process is spontaneous (galvanic cell) If E°cell < 0, then the process is non-spontaneous (the voltage must be supplied, as in an electrolytic cell).
therefore, the reaction goes by spontaneous
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