Answer to Question #347596 in General Chemistry for Ana rose

Question

A student collects 25 mL of gas at 96 kPa. What volume would this gas

        occupy at 101.325 kPa. There’s no change in temperature or mass.

Answer 1

Given:

P₁ = 96 kPa

V₁ = 25 mL

T = constant

P₂ = 101.325 kPa

V₂ = unknown

Formula: P₁V₁ = P₂V₂

Solution:

Since the temperature and amount of gas remain unchanged, Boyle's law can be used.

Boyle's gas law can be expressed as: P₁V₁ = P₂V₂

To find the volume, solve the equation for V₂:

V₂ = P₁V₁ / P₂

V₂ = (96 kPa × 25 mL) / (101.325 kPa) = 23.686 mL = 23.7 mL

V₂ = 23.7 mL

Answer: The volume of gas is 23.7 mL