In this unbalaced chemical reaction.
Fe3O4 + H2O --------> Fe + H2O
How many grams of H2O will be produced, if 41.95g of Fe3O4 are reacted completely with hydrogen? Show the solution.
Fe3O4 + 4H2 -------->3Fe + 4H2O
m(H2O) = (m( Fe3O4) * 4Mr(H2O)) / Mr(Fe3O4)
m(H2O) = (41.95 g * 4 * 18 g/mol) / 231.5 g/mol = 13.05 g
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