In the chemical reaction below, how many grams of HCl will be lrodiced by the reaction 2343.42g of CCl4? Show the solution.
CCl4 + 2HF -------> CCl2F2 + 2HCl
Solution:
The molar mass of CCl4 is 153.82 g/mol
Therefore,
Moles of CCl4 = (2343.42 g CCl4) × (1 mol CCl4 / 153.82 g CCl4) = 15.2348 mol CCl4
Balanced chemical equation:
CCl4 + 2HF → CCl2F2 + 2HCl
According to stoichiometry:
1 mol of CCl4 produces 2 mol of HCl
Thus, 15.2348 mol of CCl4 produce:
(15.2348 mol CCl4) × (2 mol HCl / 1 mol CCl4) = 30.4696 mol HCl
The molar mass of HCl is 36.458 g/mol
Therefore,
Mass of HCl = (30.4696 mol HCl) × (36.458 g HCl / 1 mol HCl) = 1110.86 g HCl
Answer: 1110.86 grams of HCl will be prodiced by the reaction.
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