How many grams of NH3 will be produced, if 97.77g of CaCO3 are also produced in the reaction below? Show the solution
If the reaction is CaCN2 + 2H2O = CaCO3 + 2NH3 then
n(CaCO3) = m/M
n(CaCO3) = 97.77/100 = 0.9777 mole
n(NH3) = 1.955 mole
m(NH3) = 1.955•17 = 33.24 g
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