Balance the following equations, using the oxidization number method for the redox part of the equation. Show your work.
A. Cu2O(s) + H2(g) —> Cu(s) + H2O(l)
B. Cl2(g) + KBr(aq) —> Br2(l) + KCl(aq)
A.
we write the degree of oxidation on the top each element in the reaction equation:
Cu2+O2– + H20 = Cu0 + H2+O2–
we write the pre- and post-reaction states of elements with changed oxidation states and the number of electrons involved in its change:
Cu+ + 1 e- —> Cu0 1
H20 – 2 e- —> 2H+ 2
We write the number of electrons involved in the change of the first element as a coefficient for the second element. We write the number of electrons involved in the change of the second element as the coefficient of the first element:
Cu2O + H2 = 2 Cu + H2O
B.
we write the degree of oxidation on the top each element in the reaction equation:
Cl20 + K+Br– = Br20 + K+Cl–
we write the pre- and post-reaction states of elements with changed oxidation states and the number of electrons involved in its change:
Cl20 + 2 e- —> 2Cl– 2
2 Br– – 2 e- —> Br20 2
We write the number of electrons involved in the change of the first element as a coefficient for the second element. We write the number of electrons involved in the change of the second element as the coefficient of the first element:
Cl2 + 2 KBr = Br2 + 2 KCl
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