Answer to Question #345718 in General Chemistry for lebron

Question

You have 2.2 mol Xe and 4.0 mol F₂, but when you carry out the reaction you end up with only 0.25 mol XeF₄. What is the percent yield of this experiment?

Xe(g) + 2 F₂ (g) → XeF₄ (g)

Answer 1

Xe + 2 F₂ = XeF₄

According to the above reaction, 1 mole of Xe reacts with 2 moles of F₂ to form 1 mole of XeF₄

2mol F₂ => 1mol XeF₄

4mol F₂ => X

X = 4 * 1 / 2 = 2 mol XeF₄

if the reaction proceeds with 100% efficiency, 2 mol XeF₄ is formed. We find the yield of 0.25 mol of XeF₄

2mol — 100%

0,25mol — X

X = 0,25 * 100 / 2 = 12,5 %

ANSWER: 12,5%