Answer to Question #345658 in General Chemistry for Stacka

Question

2 Al + 3 CuCh2 -› 2 AICl, + 3 Cu

Molar masses: 27.0 g/mol Al,

134.5 g/mol CuCh2, 63.5 g/ mol

Cu

Question 1: How many grams of CuCh2 are

necessary to consume 10 g Al?

Question 2: How many grams of Cu will be

produced?

Answer 1

According to the following reaction, when 2 mol (54 g) of Al reacts, 3 mol (405 g) of CuCl₂ reacts to form 3 mol (192 g) of Cu.

2Al + 3CuCl₂ = 2AlCl₃ + 3Cu

1.

When 10 g of Al reacts, we find how many g of CuCl₂ react:

54 g Al — 405 g CuCl₂

10 g Al — X

X = 10 * 405 / 54 = 75 g CuCl₂

2.

We find how many grams of Cu are formed when 10 g of Al reacts:

54 g Al — 192 g Cu

10 g Al — X

X = 10 * 192 / 54 = 35,56 g Cu