25.0 g H, are reacted, how much Fe is
produced?
Molar masses: 2.02 %mol Ha, 55.9 %/mol Fe
A. 0.903 g Fe
B. 1,112 g Fe
C. 692 g Fe
D. 346 g Fe
Fe2O3 + 3H2 = 2Fe + 3H2O
m(Fe) = (m(H2)•2Mr(Fe)) / 3Mr(H2)
m(Fe) = (25 g • 2•55.9 g/mol) / 3•2.02 g/mol = 461.2 g
m(Fe) = 25•55.9/2.02 = 692 g
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