How many grams of H2O will be produced by the combustion of 73.56 grams of C2H4?
C2H4 + 3O2 ------> 2CO2 + 2H2O
Show the solution.
m(H2O) = (m( C2H4) • 2Mr(H2O)) / Mr(C2H4)
m(H2O) = (73.56 g • 2•18 g/mol) / 28 g/mol = 94.58 g
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