Answer to Question #345474 in General Chemistry for Han

Question

If 17.4 g of HF is used, what mass of H2SiF6 is produced? Show the solution

Answer 1

8HF + Na₂SiO₃ = H₂SiF₆ + 2NaF + 3H₂O

According to the above reaction, 8 mol or 160gr HF (20gr / mol) reacts to form 1 mol or 144gr H₂SiF₆ (144 gr/mol). We find how many grams of H₂SiF₆ are formed when 17.4 g of HF reacts:

160gr HF — 144gr H₂SiF₆

17,4gr HF — X gr H₂SiO₆

X = 17,4 * 144 / 160 = 15,66 gr

ANSWER: 15,66 gr H₂SiF₆