Answer to Question #345473 in General Chemistry for Han

Question

28.0 g of magnesium carbonate reacts with sulfuric acid. What mass of water is produced? Show the solution.

Answer 1

MgCO₃ + H₂SO₄ = MgSO₄ + H₂O

According to the above reaction, 1mol (84 g) of MgCO₃ reacts to form 1 mol (18 g) of H₂O (water). We find how much H₂O is formed when 28 g of MgCO3 reacts:

84gr MgCO₃ — 18gr H₂O

28gr MgCO₃ — X gr H₂O

X = 28 * 18 / 84 = 6 gr

ANSWER: 6 gr H₂O