Question #345465
what is the percentage yield of 9.28 g of oxygen react with hydrogen to produce 8.81 g of water? Show the solution
Expert's answer
2H2 + O2 = 2H2O
n(O2) = 9.28/32 = 0.29 mole
n(H2O) = 0.58 mole
m(H2O) = 10.44 g
yield = 8.81/10.44 =
84.4%
