if 18.8 ml of 1.25 m sodium hydroxide solution is necessary to neutralize 25.0 ml of hydrochloric acid solution to a phenolphthalein end point, calculate the molarity of the hydrochloric acid solution
HCl + NaOH = NaCl + H2O
1. Using the formula n = CM * V , we find how many moles of NaOH. In the formula,
n — amount of solute (mol);
CM — concentration of molarity (mol/l);
V — volume of solution (litres):
n = 1,25 * 0,0188 = 0,0235 mol NaOH
2. According to the above reaction, 1 mol of NaOH reacts with 1 mol of HCl. We find how many moles of HCl react with 0.0235 mol NaOH:
1mol NaOH — 1mol HCl
0,0235mol NaOH — X mol HCl
X = 0,0235mol HCl
3. We find the molar concentration of HCl using the following formula:
CM = n / V = 0,0235 mol / 0,025 litres = 0,94
ANSWER: 0,94 mol/l HCl
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