Answer to Question #345105 in General Chemistry for alex

Question

Given the reaction:

2 NaOH + H₂SO₄ ⟶

  Na₂SO₄ + 2 H₂O 

How many moles of sodium sulfate (Na₂SO₄) reproduced when 9.9 moles of sodium hydroxide (NaOH) are reacted with excess sulfuric acid?

Answer 1

2NaOH + H₂SO₄ —> Na₂SO₄ + 2H₂O

According to the above reaction, 2 mol of NaOH reacts to form 1 mole of Na₂SO₄. How many moles of Na₂SO₄ are formed when 9.9 moles of NaOH react:

2 mol NaOH — 1mol Na₂SO₄

9,9 mol NaOH — X mol Na₂SO₄

X = 9,9 * 1 / 2 = 4,95 mol

ANSWER: 4,95 mol Na₂SO₄