Answer to Question #344380 in General Chemistry for Lee

Question #344380

How many moles are in 987.0 grams of Ra(OH)2

Expert's answer

m(Ra(OH)₂) = 987.0 g

M(Ra(OH)₂) = 260.o g/mol

m = n*M

n = m/M = 987.0 g / 260.o g/mol = Ra(OH)₂)

Answer:

n(Ra(OH)₂) = Ra(OH)₂)

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