Answer to Question #344380 in General Chemistry for Lee

Question

How many moles are in 987.0 grams of Ra(OH)2

Answer 1

m(Ra(OH)₂) = 987.0 g

M(Ra(OH)₂) = 260.o g/mol

m = n*M

n = m/M = 987.0 g / 260.o g/mol = Ra(OH)₂)

Answer:

n(Ra(OH)₂) = Ra(OH)₂)