Answer to Question #344270 in General Chemistry for kaekae

Question

If 15.0 of phosphoric acid completely neutralizes 38.5mL of 0.150 mol/L sodium hydroxide, what is the concentration of the phosphoric acid

Answer 1

The amount of mole at the neutralization point is equal:

$n_1=n_2$

$c_1V_1=c_2V_2$

$c_1 = \frac{c_2V_2}{V_1} = \frac{0.150 mol/L\times 38.5 ml}{15.0 ml} = 0.385 mol/L$