Answer to Question #344157 in General Chemistry for Meg

Question

What is the molarity of a KOH solution if 25.0 mL of it is neutralized by 42.6 mL of a 0.100 M nitric acid solution? Show your work.

Answer 1

Solution:

Balanced chemical equation:

KOH + HNO₃ → KNO₃ + H₂O

According to stoichiometry:

Moles of KOH = Moles of HNO₃

Molarity of KOH × Volume of KOH = Molarity of HNO₃ × Volume of HNO₃

Therefore,

Molarity of KOH = (Molarity of HNO₃ × Volume of HNO₃) / (Volume of KOH)

Molarity of KOH = (0.100 M × 42.6 mL) / (25.0 mL) = 0.170 M

Molarity of KOH = 0.170 M

Answer: The molarity of KOH solution is 0.170 M