Question

If the temperature is decreased to 5 °C, what is the volume of the sample if the pressure is increased to 96.0 kPa?

Answer 1

In gases, the change in volume is directly proportional to temperature and inversely proportional to pressure. That is,

V / V₀ = T / T₀ = P₀ / P

in the formula:

V – final volume = X

V₀ – initial volume = 22,4 l

T – final temperature = 5° C = 278 K

T₀ –initial temperature = 20° C = 298 K

P – final pressure = 96 kPa

P₀ – initial pressure = 101,325 kPa

V = P₀ * V₀ * T / P * T₀

V = 101,325 * 22,4 * 278 / 96 * 298 = 22,06 l

comment: Since the initial conditions and gas volume were not given in the assignment, 1 mole of gas under normal conditions was taken.

ANSWER: 22,06 litres