If the temperature is decreased to 5 °C, what is the volume of the sample if the pressure is increased to 96.0 kPa?
In gases, the change in volume is directly proportional to temperature and inversely proportional to pressure. That is,
V / V0 = T / T0 = P0 / P
in the formula:
V – final volume = X
V0 – initial volume = 22,4 l
T – final temperature = 5° C = 278 K
T0 –initial temperature = 20° C = 298 K
P – final pressure = 96 kPa
P0 – initial pressure = 101,325 kPa
V = P0 * V0 * T / P * T0
V = 101,325 * 22,4 * 278 / 96 * 298 = 22,06 l
comment: Since the initial conditions and gas volume were not given in the assignment, 1 mole of gas under normal conditions was taken.
ANSWER: 22,06 litres
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