Find the formula of the compound with the percent composition shown
O, 41.26
P, 19.97
Ca 38.76
1. We divide the mass fraction of each element by its relative atomic mass:
O — 41,26 / 16 = 2,57875
P — 19,97 / 31 = 0,6442
Ca — 38,78 / 40 = 0,9695
2. We divide each of the results into the smallest of them.(the smallest here is 0,6442):
O — 2,57875 / 0,6442 = 4
P — 0,6442 / 0,6442 = 1
Ca — 0,9695 / 0,6442 = 1,5
3. we can express the result in whole numbers. to do this, we multiply each of the results by 2 or 3, and so on. (until an integer is formed):
O — 4 * 2 = 8
P — 1 * 2= 2
Ca — 1,5 * 2 = 3
The result Ca = 3, P = 2, O = 8
The substance with this composition is Ca3(PO4)2 calcium phosphate
ANSWER: Ca3(PO4)2
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