Answer to Question #342975 in General Chemistry for aya

Question

A sample of oxygen gas (O

2

) has a volume of

9

.0 L and a pressure of

2

.0 atm. What is the new

pressure if the volume is decreased to

3

.0 L?

Answer 1

Given:

P₁ = 2.0 atm

V₁ = 9.0 L

T₁ = T₂ = constant

P₂ = unknown

V₂ = 3.0 L

Formula: P₁V₁ = P₂V₂

Solution:

Since the temperature and amount of gas remain unchanged, Boyle's law can be used.

Boyle's gas law can be expressed as: P₁V₁ = P₂V₂

To find the new pressure of oxygen gas, solve the equation for P₂:

P₂ = P₁V₁ / V₂

P₂ = (2.0 atm × 9.0 L) / (3.0 L) = 6.0 atm

P₂ = 6.0 atm

Answer: The new pressure of oxygen gas is 6.0 atm