One of the reactions used to inflate automobile air bags involves sodium azide
(NaN3). The balanced equation will be: 2NaN3(s) → 2Na(s) + 3N2(g). Determine the mass of N2
produced from the decomposition of 100.0 g of NaN3.
The mol number of sodium azide:
n(NaN3)=m(NaN3)M(NaN3)=100.0g65.0g=1.54moln(NaN_3) = \frac{m(NaN_3)}{M(NaN_3)}=\frac{100.0 g}{65.0g } = 1.54 moln(NaN3)=M(NaN3)m(NaN3)=65.0g100.0g=1.54mol
By the balanced reaction we observed following:
2n(NaN3)=3n(N2)2n(NaN_3) = 3n(N_2)2n(NaN3)=3n(N2)
n(N2)=23n(NaN3)n(N_2) = \frac{2}{3}n(NaN_3)n(N2)=32n(NaN3)
m(N2)=n(N2)×M(N2)=23n(NaN3)×M(N2)m(N_2) = n(N_2) \times M(N_2) = \frac{2}{3}n(NaN_3) \times M(N_2)m(N2)=n(N2)×M(N2)=32n(NaN3)×M(N2)
m(N2)=23×1.54mol×14g/mol=14.4gm(N_2) = \frac{2}{3} \times 1.54 mol \times 14 g/mol = 14.4 gm(N2)=32×1.54mol×14g/mol=14.4g
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