Question

NH4NO3(s) → N2O(g) + 2H2O(l)

In a certain experiment, 156 g of ammonium nitrate is decomposed. Find the mass of each of the products formed.

Answer 1

$M(NH_4NO_3)=14+4x1+14+16x3=80 g/mole$

$M(N_2O)=14x2+16=44 g/mole$

$M(H_2O)=2x1+16=18 g/mole$

$n(NH_4NO_3)=156/80=1.95 mole$

$n(N_2O)=n(NH_4NO_3)=1.95 mole$

$n(H_2O)=2n(NH_4NO_3)=1.95x2=3.9 mole$

$m(N_2O)=1.95x44=85.8 g$

$m(H_2O)=3.9x18=70.2 g$