Answer to Question #342414 in General Chemistry for Kian

Question

if it takes 24.8 ml of 1.20N acid to neutralize 3.25 g of a base, what is the equivalent weight of the base

Answer 1

1. Using the formula C_N = n_equ / V, we obtain the formula for finding nekv: n_equ = C_N * V. where,

C_N – is the normal concentration,

n_equ – is the equivalent amount of the substance,

V – is the volume.

n_equ = C_N * V = 1,2 * 0.0248 = 0.02976

hence the equivalent amount of reacting acid is 0.02976. 

2. substances react in equal equivalent amounts with each other. therefore the equivalent amount of reacting base is also 0.02976.

3. Using the M_equ = m / n_equ formula, we find the equivalent mass of the acid. To do this, we divide the mass of the acid by its equivalent amount:

M_equ = m / n_equ = 3,25 / 0.02976 = 109.2

ANSWER: 109.2 gr/equivalent