Question

An expandable container of oxygen gas has a volume of 12.5mL at a temperature of 26.0°C. What volume will the gas occupy at 54.0°C?

Answer 1

One of the forms of Charles’s low when the pressure is constant:

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

With the increase of temperature volume of a gas become:

$V_2 = \frac{V_1 \times T_2}{T_1} = \frac{12.5 ml \times 54}{26} = 26 ml$