Answer to Question #341983 in General Chemistry for Harmony

Question

The air-dried and sieved soil was placed into pots with a 25 cm diameter and a 27 cm height (8 kg per pot). Sulphur was used as the S source and the application rates were 0, 150, 300 mg kg−1 . The Se source was sodium selenite (Na2SeO3) and it was applied at 0 and 15 mg kg−1.

I will like to understand how they got the amount of selenite and sulphur added to the pot experiment?

Answer 1

If application rates of S are 0,150,300 mg/kg, then on 8 kg there are 0x8=0mg, 150x8=1200mg, 300x8=2400mg.

As Se was applied 0, 15 mg/kg, then on 8 kg it needs 8x0=0 mg, 15x8=120 mg