1.Calculate the enthalpy change for the following chemical reaction:
SC2(l) + 3O@(g) --> CO2(g) + 2SO2(g)
1.C(s) + O2(g) --> CO2(g) ΔH° = - 393.5 kJ
2.S(s) + O2(g) --> SO2(g) ΔH° = - 296.8 kJ
3.C(s) + 2S(s) --> CS2(l) ΔH° = + 87.9 kJ
ΔHreaction = ∑ΔHproducts − ∑ΔHreactants
ΔHreaction = (- 393.5 kJ + 2*(-- 296.8 kJ)) - 87.9 kJ = - 1075 kJ
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