Balance the following redox reaction that takes place in an acidic solution using the oxidation number method: Fe203(s)+CO(g)-Fe3(aq)+Cr3+(aq)
Fe2O3(s)+3CO(g)→2Fe(s).+3CO2(g)Fe_2O_3{(s)}+3CO_{(g)} \rightarrow 2Fe _{(s)}. + 3CO_{2(g)}Fe2O3(s)+3CO(g)→2Fe(s).+3CO2(g)
Fe+3−3e→Fe0(1)Fe^{+3}-3e \rightarrow Fe^0 (1)Fe+3−3e→Fe0(1)
C+2+2e→C+4(2)C^{+2} +2 e\rightarrow C^{+4} (2)C+2+2e→C+4(2)
So we should multiply reaction 1 on 2, and reaction 2 on 3.
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