Answer to Question #341778 in General Chemistry for Masnon

Question

How many number of atoms does contain in 7g KOH(POTASSIAM HIDRO OXIDE)?

Answer 1

M(KOH)=39+16+1=56 g/mole

n(KOH)=7/56=0.125 mole

1 mole contains 6.02x10²³ molecules, then 0.125 mole contains 0.125x6.02x10²³=0.7525 x10²³ molecules. Rach molecule contains 3 atoms: K,O,H, so it is 0.7525x3x10²³ =2.2575 x10²³ atoms