A 20.0-L volume of methane gas is heated from 25°C to 70°C at constant pressure. What is the final volume of the gas?
According to Gay Lussac's law, the change in temperature at constant pressure is directly proportional to the volume. that is, V1 / V2 = T1 / T2
we must first transfer the temperature to the kelvin:
T1 = 25+273= 298K
T2 = 70+273= 343K
V1 = 20 L
V1 / V2 = T1 / T2
20/X = 298/343;
X = 20 * 343 / 298 = 23L
ANSWER: 23 L
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