Answer to Question #340994 in General Chemistry for Vvununim

Question

When 1.1.2g of iron reacts with 32g of bromine , iron (III)bromide is produced. Find the mass of iron (III) bromide.

Answer 1

2Fe + 3Br₂ = 2FeBr₃

n(Fe) = 11.2 g / 55.8 g/mol / 2 = 0.1 moles

n(Br₂) = 32 g / 159.8 g/mol / 3 = 0.07 moles

Fe - excess reagent

Br₂ - limiting reagent

m(FeBr₃) = (m(Br₂) * 2Mr(FeBr₃)) / 3Mr(Br₂) = (32 g * 2*295,56 g/mol) / 3*159.8 g/mol = 39.46 g