Question

Calculate the number of milliliters of solution required to provide the following:

a. 17.5 g of sulfuric acid from a 2.50 N solution in reactions that replace both hydrogen ions.

b. 24.2 g of calcium chloride from a 1.25 N solution in reactions that replace both chloride ions.

Answer 1

$c((H_2SO_4)=2.5 n=2.5/2=1.25 M$

$M(H_2SO_4)=2x1+32+16x4=98 g/mole$

$n(H_2SO_4)=17.5 /98=0.179 mole$

$V(H_2SO_4)=0.179/1.25=0.1428 l=142.8 ml$

b.$c(CaCl_2)=1.25 n=1.25/2=0.625 M$

$M(CaCl_2)=40+2x35.5=111 g/mole$

$n(CaCl_2)=24.2/111=0.218 mole$

$V(CaCl_2)=0.218/0.625=0.3488 l=348.8 ml$