Calculate the number of milliliters of solution required to provide the following:
a. 17.5 g of sulfuric acid from a 2.50 N solution in reactions that replace both hydrogen ions.
b. 24.2 g of calcium chloride from a 1.25 N solution in reactions that replace both chloride ions.
"c((H_2SO_4)=2.5 n=2.5\/2=1.25 M"
"M(H_2SO_4)=2x1+32+16x4=98 g\/mole"
"n(H_2SO_4)=17.5 \/98=0.179 mole"
"V(H_2SO_4)=0.179\/1.25=0.1428 l=142.8 ml"
b."c(CaCl_2)=1.25 n=1.25\/2=0.625 M"
"M(CaCl_2)=40+2x35.5=111 g\/mole"
"n(CaCl_2)=24.2\/111=0.218 mole"
"V(CaCl_2)=0.218\/0.625=0.3488 l=348.8 ml"
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