How many grams of magnesium hydroxide are there in 125 m/ of 3.50 N solution?
Molarity=Normality/Valence factor=3.5 N / 2= 1.75 M
n(Mg(OH)2) = CM * V = 1.75 M * 0.125 L = 0.219 moles
m(Mg(OH)2) = n(Mg(OH)2) * Mr(Mg(OH)2) = 0.219 moles * 58.33 g/mol = 12.77 g
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