How many milliliters of 0.35 N sulfuric acid are necessary to react with 30.2 m/ of 0.52 N sodium hydroxide)
"z(H_2SO_4)=2"
"c(H_2SO_4)=0.35\/z=0.35\/2=0.175 M"
"z(NaOH)=1"
"c(NaOH)=0.52\/1=0.52 M"
"H_2SO_4+2 NaOH \\rightarrow Na_2SO_4 +2H_2O"
"n(NaOH)=0.52x0 0302=0.015704 mole"
"n(H_2SO_4)=n(NaOH)\/2=0.015704\/2=0.007852 mole"
"V=n(H_2SO_4)x1000\/c(H_2SO_4)=0.007852x1000\/0.175=44.9 ml"
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